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mysql - 查询表里边id为16的content然后,更新id大于16的content为查出来的content
问题描述
问题解答
回答1:update guideline_news set content =(select content from (select * from guideline_news) a where a.id = 16) where id>16;
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问题描述
问题解答
回答1:update guideline_news set content =(select content from (select * from guideline_news) a where a.id = 16) where id>16;