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Python 怎么操作windows系统服务

浏览:46日期:2022-06-28 11:48:35

问题描述

def listservices(): import wmi c = wmi.WMI() for service in c.Win32_Service():#print(service.Caption,service.StartMode,service.State)print(service.Caption) #名称print(service.StartMode) #启动类型print(service.State) #状态if __name__==’__main__’: listservices()

怎么更改启动类型以及状态呢?

问题解答

回答1:

模块作者的文档里有例子

http://timgolden.me.uk/python...

import wmic = wmi.WMI()for service in c.Win32_Service(Name='seclogon'): result, = service.StopService() if result == 0: print 'Service', service.Name, 'stopped' else: print 'Some problem' breakelse: print 'Service not found'

标签: Windows系统
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