python - scrapy xpath 页面解析找不到

问题描述

下面是页面大类的html

<p class='house-item clearfix house-item-curr'><p class='item-photo fl'> <a href='https://www.haobala.com/zufang/shbs12427828.html' target='_blank'><img src='https://imgsh.centanet.com/ctpostimage/a4/d5/4e4da3a2496299b2b26243565af6_220x165.jpg' src='https://imgsh.centanet.com/ctpostimage/a4/d5/4e4da3a2496299b2b26243565af6_220x165.jpg' alt='采菊苑租房2800元/月' style='display: inline-block;'></a></p><p class='item-info fl'> <h4 class='house-title'><a href='https://www.haobala.com/zufang/shbs12427828.html' target='_blank' class='cBlueB'>采菊苑，77平两房出租，毛坯3千，好谈价！</a> </h4> <p class='f14 f000 mb_10'><a href='https://www.haobala.com/xiaoqu/xq-pedpwawows/' target='_blank'>采菊苑</a><span class='f000 mr_10'>2室2厅</span><span class='f000'>77平</span> </p> <p class='f7b mb_10'>南北<em class='mrl_6'>|</em>高层<em class='mrl_6'>|</em>毛坯<em class='mrl_6'>|</em>2008年<em class='mrl_6'>|</em>整租 </p> <p class='f7b mb_15'>宝山-顾村 菊联路68弄<a href='javascript:void(0)' value='/page/v1/common/maputil.aspx?x=121.372168&amp;y=31.354713' class=' icons_map jsmapicon '></a> </p> </p> <p class='item-pricearea fr'> <p class='price-nub cRed'>2800元/月</p> <p class='f14 f000 mb_15 fsm'>&nbsp;</p> </p><p class='clear'></p> </p>

我用xpath提取text 我的代码是

class itcast(scrapy.Spider): name = ’SH’ allowd_domains = ['http://sh.centanet.com/'] start_urls = ['http://sh.centanet.com/zufang/p2/'] def parse(self,response):list = response.xpath('//p[@class=’//p[@class=’ouse-item clearfix house-item-curr’]')for i in list: name = i.xpath('//a[@class=’cBlueB’.text()]') print name[0]

我可以找到这个大类报错是在 for i in list：name =f.xpath()这行，text提取不到。执行代码找不到，帮我看看我是哪里不对，类似的我也试过好多次，没办法了，只能提问了希望能回答下 谢谢！

问题解答

def parse(response): list = response.xpath('//p[@class=’house-item clearfix house-item-curr’]') for i in list:name = i.xpath('//a[@class=’cBlueB’]')print name[0].text

也许你是这个意思？

name = i.xpath('//a[@class=’cBlueB’.text()]')这种写法是错误的，text怎么能放在[]里面呢