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socket编程 - python如何进行socket连接

【字号: 日期:2022-09-01 14:33:18浏览:12作者:猪猪

问题描述

尝试连接 119.23.124.81:7575

服务器每5秒会返回一个{'type':'ping'},我尝试用以下代码去连接,但是无法获取到这个{'type':'ping'}:

s = socket(AF_INET, SOCK_STREAM)# 建立连接:s.connect((’119.23.124.81’, 7575))while True: print(s.recv(1024).decode(’utf-8’))s.close()

代码不会报错,但是也获取到我想要的内容

请问要如何写才能获取到这个{'type':'ping'}

问题解答

回答1:

搞清楚了,原来这个是使用的websocket协议,不是普通的socket

换用websocket这个库就好了,代码如下:

from websocket import create_connectionws = create_connection('ws://42.96.131.185:7575')print('Sending ’Hello, World’...')for i in range(10000): ws.send(b'Hello, World') print('Sent')print('Reeiving...')result = ws.recv()print('Received ’%s’' % result)ws.close()回答2:

参考官方文档

# Echo server programimport socketHOST = ’’ # Symbolic name meaning all available interfacesPORT = 50007 # Arbitrary non-privileged ports = socket.socket(socket.AF_INET, socket.SOCK_STREAM)s.bind((HOST, PORT))s.listen(1)conn, addr = s.accept()print ’Connected by’, addrwhile 1: data = conn.recv(1024) if not data: breakconn.sendall(data)conn.close()

and

import SocketServerclass MyTCPHandler(SocketServer.BaseRequestHandler):'''The request handler class for our server.It is instantiated once per connection to the server, and mustoverride the handle() method to implement communication to theclient.''' def handle(self):# self.request is the TCP socket connected to the clientself.data = self.request.recv(1024).strip()print '{} wrote:'.format(self.client_address[0])print self.data# just send back the same data, but upper-casedself.request.sendall(self.data.upper())if __name__ == '__main__': HOST, PORT = 'localhost', 9999 # Create the server, binding to localhost on port 9999 server = SocketServer.TCPServer((HOST, PORT), MyTCPHandler) # Activate the server; this will keep running until you # interrupt the program with Ctrl-C server.serve_forever()回答3:

因为你发送的数据是一个字典对象,所以在socket发送据时,用pickle或者json模块对数据进行序列化再发送,对应的,接收端要用pickle或者json进行反序列化操作。

标签: Python 编程
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