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PHP类封装的插入数据,总是插入不成功,返回false;

【字号: 日期:2022-06-01 11:23:54浏览:150作者:猪猪

问题描述

<?php//数据库操作类class Model{ private $host; //数据库地址 private $user; //数据库用户名 private $pwd; //数据库密码 private $tabName; //表名 private $preFix; //表前缀 private $dbName; //数据库名 private $charset; //字符 private $link=null; //数据连接对象 function __construct($tabName = ''){$this->host = DB_HOST;$this->user = DB_USER;$this->pwd = DB_PWD;$this->charset = CHARSET;$this->preFix = DB_PREFIX;$this->dbName = DB_NAME;if($tabName == ''){ $this->tabName = $this->prefix.strtolower(substr(get_class($this),0,-5)) ;}else{ $this->tabName = $this->preFix.$tabName;}$this->link = $this->connect(); } private function connect(){$link = @mysqli_connect($this->host,$this->user,$this->pwd,$this->dbname) or die('数据库连接错误');if(!$link){ return false;}mysqli_set_charset($link,$this->charset);return $link; } public function insert(array $data){//var_dump($data);//INSERT INTO user(name,sex,age) VALUE();$key = $val = '';foreach($data as $k=>$v){ $key .='`'.$k.'`,'; $val .="'".$v."',";}$key = rtrim($key,',');$val = rtrim($val,',');// var_dump($key);// var_dump($val);$sql = "INSERT INTO {$this->tabName} ({$key}) VALUES ({$val})";echo $sql;return $this->exec($sql); } private function exec($sql){$result = mysqli_query($this->link,$sql);if($result && mysqli_affected_rows($this->link) > 0){ return mysqli_insert_id($this->link) ?? mysqli_affected_rows($this->link);}else{ return false;} }}//调用方法,为什么不成功?总是插入不进去,提示false;??<?php$m = new Model('user');// echo '<pre>';// var_dump($m);$_POST = array('name'=>'小驴','age'=>'20','sex'=>'1');$result = $m->insert($_POST);var_dump($result);

问题解答

回答1:

终于知道原因了!!已搞定!

回答2:

PHP类封装的插入数据,总是插入不成功,返回false;

按照代码应该是连接的问题,你可以尝试打印$link

回答3:

看代码也没有问题,sql语句在数据库中也是可以正常执行的,但是调用类的插入方法之后,就不行了,这是怎么回事?