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javascript - 又是this指向问题

浏览:115日期:2023-04-21 11:28:45

问题描述

这是一个星星评分插件,用原生js写的。将for(var k = 0)...这一段抽出来时,然后执行到that.getStarPoint.call(this,point,active)这部分就不行了,这个this是指向star[i],如何将star[i]和star[k]有相同的作用呢?

html: (星星暂时用颜色块代替)

<!DOCTYPE html><html><head> <meta charset='utf-8'> <title>星星评分插件</title> <meta name='renderer' content='ie-webkit'> <style>.star{ margin-top: 10px;}.star span, .star em{ display: inline-block; vertical-align: top;}.star span{ cursor: pointer; width: 16px; height: 16px; background: #eee;}.star span.active{ background: #333;} </style></head><body> <!-- 建议放评分的盒子也放在同一个盒子里面并且与星星的标签不一样,这样方面dom查找 --> <!-- 星星可以是图片,也可以放在css里面 --> <p class='star'><span></span><span></span><span></span><span></span><span></span><em class='star-point'></em> </p></body> <script type='text/javascript' src='https://www.haobala.com/wenda/common.js'></script> <script type='text/javascript'>new Star(’.star’); </script></html>

js:

;(function(global,undefined){ ’use strict’ var _global; function Star(options){this.defaultOptions = { starBox: ’.star’, //装星星的obj starActive: ’active’, //鼠标移上去的样式 starPoint: ’.star-point’ //星星评分};this.opt = this.extend(this.defaultOptions, options || {} || ’’);this.star = this.getElem(this.opt.starBox).getElementsByTagName(’span’);this.len = this.star.length;this.init(options); } Star.prototype = {constructor: this,init: function(options){ var that = this; var starBox = that.getElem(that.opt.starBox),starPoint = that.getElem(that.opt.starPoint),active = that.opt.starActive,star = starBox.getElementsByTagName(’span’),point = 0; for(var i = 0; i<this.len; i++){star[i].index = i;star[i].onmouseover = function(){ that.clearAllStar.call(this); /*for(var k = 0; k<this.len; k++){star[k].className = ’’; }*/ for(var j = 0; j<this.index + 1; j++){star[j].className = active; //经过的就添加active类 }}star[i].onmouseout = function(){ for(var j = 0; j<this.index + 1; j++){star[j].className = ’’; //离开的就去掉active类 } //公用部分 /*for(var k = 0; k<point; k++){star[k].className = active; }*/ that.getStarPoint.call(this,point,active);}star[i].onclick = function(){ //点击后的星星个数以及分数 point = this.index + 1; starPoint.innerHTML = point + ’分’; //公用部分 /*for(var k = 0; k<point; k++){star[k].className = active; }*/that.getStarPoint.call(this,point,active);} }},clearAllStar: function(){ //清理所有hover过的星星 for(var k = 0; k<this.len; k++){this.className = ’’; }},getStarPoint: function(point,active){ //获取评分 for(var k = 0; k<point; k++){this.className = active; }},getElem: function(obj){ //获取dom元素 return document.querySelector(obj);},extend: function(source,value){ //拓展参数的函数 for(var i in value){if(value.hasOwnProperty(i)){ source[i] = value[i];} } return source;} }}())

问题解答

回答1:

感觉把 this 绑到 getStarPoint() 意义不大,因为除了当前元素,还有前面的元素都要置为 active,不如就 循环然后 star[k].className = active;

回答2:

我觉得,你应该将that作为getStarPoint的上下文,写作that.getStarPoint.call(that, point, active);,此处that才是Star实例。

回答3:

把str数组传过去呗,getStarPoint 这个对纯粹的循环操作 ,对this是啥并无要求。

回答4:

不太理解你说的 “star[i]和star[k]有相同的作用”, 是什么意思。如果onmouseover 知道自己是哪一个star,可以用闭包把i传过去:

for(var i = 0; i<this.len; i++) {

star[i].index = i;star[i].onmouseover = (function(i) { return function(){that.clearAllStar.call(this);/*for(var k = 0; k<this.len; k++){ star[k].className = ’’;}*/for(var j = 0; j<this.index + 1; j++){ star[j].className = active; //经过的就添加active类} }})(i).....

}

标签: JavaScript
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