您的位置:首页技术文章
文章详情页

javascript - console.log问题,交换二叉树左右节点,交换前后输出相同结果

【字号: 日期:2023-05-02 08:20:30浏览:70作者:猪猪

问题描述

代码如下:

class Tree { constructor(left=null, right=null){this.v = id++;this.left = left;this.right = right; } switch() {if(null != this.left || null != this.right){ let temp = this.right; this.right = this.left; this.left = temp;}if (null != this.left) { this.left.switch();}if (null != this.right) { this.right.switch();} }}var id = 0;var A = new Tree();var B = new Tree();var C = new Tree(A, B);var D = new Tree();var E = new Tree(D);var F = new Tree(C, E);console.log(F);F.switch();console.log(F);

控制台为什么都输出交换后的结果?求解

问题解答

回答1:

应该是你看错了…… 你用 console.log(JSON.stringify(F)); 看看

标签: JavaScript