单击登录按钮无反应
问题描述
<!DOCTYPE HTML><html><head><meta charset="utf-8"><meta name="renderer" content="webkit|ie-comp|ie-stand"><meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1"><meta name="viewport" content="width=device-width,initial-scale=1,minimum-scale=1.0,maximum-scale=1.0,user-scalable=no" /><meta http-equiv="Cache-Control" content="no-siteapp" /><!--[if lt IE 9]><script type="text/javascript" src="__STATIC__/lib/html5.js"></script><script type="text/javascript" src="__STATIC__/lib/respond.min.js"></script><![endif]--><link href="__STATIC__/static/h-ui/css/H-ui.min.css" rel="stylesheet" type="text/css" /><link href="__STATIC__/static/h-ui/css/H-ui.login.css" rel="stylesheet" type="text/css" /><link href="__STATIC__/static/h-ui.admin/css/style.css" rel="stylesheet" type="text/css" /><link href="__STATIC__/lib/Hui-iconfont/1.0.8/iconfont.css" rel="stylesheet" type="text/css" /><!--[if IE 6]><script type="text/javascript" src="http://lib.h-ui.net/DD_belatedPNG_0.0.8a-min.js" ></script><script>DD_belatedPNG.fix('*');</script><![endif]--><title>后台登录 - H-ui.admin.page v3.0</title><meta name="keywords" content="H-ui.admin v3.0,H-ui网站后台模版,后台模版下载,后台管理系统模版,HTML后台模版下载"><meta name="description" content="H-ui.admin v3.0，是一款由国人开发的轻量级扁平化网站后台模板，完全免费开源的网站后台管理系统模版，适合中小型CMS后台系统。"></head><body><input type="hidden" id="TenantId" name="TenantId" value="" /><div class="header"></div><div class="loginWraper"> <div id="loginform" class="loginBox"> <form class="form form-horizontal" action="index.html" method="post"> <div class="row cl"> <label class="form-label col-xs-3"><i class="Hui-iconfont"></i></label> <div class="formControls col-xs-8"> <input id="" name="name" type="text" placeholder="账户" class="input-text size-L"> </div> </div> <div class="row cl"> <label class="form-label col-xs-3"><i class="Hui-iconfont"></i></label> <div class="formControls col-xs-8"> <input id="" name="password" type="password" placeholder="密码" class="input-text size-L"> </div> </div> <div class="row cl"> <div class="formControls col-xs-8 col-xs-offset-3"> <input name="verify" class="input-text size-L" type="text" placeholder="验证码" onblur="if(this.value==''){this.value='验证码:'}" onclick="if(this.value=='验证码:'){this.value='';}" value="" style="width:150px;"> <img id="verify_img" src="{:captcha_src()}"> <a id="kanbuq" href="javascript:refreshverify();">看不清，换一张</a> </div> </div> <div class="row cl"> <div class="formControls col-xs-8 col-xs-offset-3"> <label for="online"> <input type="checkbox" name="online" id="online" value=""> 使我保持登录状态</label> </div> </div> <div class="row cl"> <div class="formControls col-xs-8 col-xs-offset-3"> <input name="" type="button" id="login" class="btn btn-success radius size-L" value=" 登 录 ">
</div> </div> </form> </div></div>
<script type="text/javascript" src="__STATIC__/lib/jquery/1.9.1/jquery.min.js"></script><script type="text/javascript" src="__STATIC__/static/h-ui/js/H-ui.js"></script><!--Ajax提交脚本-- ><script>$(function(){ //给登录按钮添加点击事件 $("#login").on('click',function(event){ $.ajax({ type: "POST",//提交方式为POST url: "{:url('checklogin')}",//设置提交数据处理的文件地址 data: $("form").serialize(),//将表彰系列化后提交 datatype: 'json',//设置提交数据类型为是json success: function(data) { //只有返回标志位为，再处理alert(data); } }) })})</script><!--刷新验证码的脚本--><script>
function refreshverify(){ var ts = Date.parse(new Date())/1000;// $("verify_img").attr("src" , "/captcha?id="+ts);//刷新验证码图片 var img = document.getElementById('verify_img'); img.src = "/captcha?id="+ts;
}</script></body></html>
public function checklogin(Request $request) {//初始返回参数 $status=0; $result=''; $data=$request -> param(); return['status'=>$status,'message'=>$result,'data'=>$data];
}
问题解答
回答1：ajax用post提交还有一个参数没写吧相关文章：
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