登录页面点击登录后查询不出数据,无法成功登陆,但是在数据库中进行查询操作是可以成功的,是什么原因呢?
问题描述
<?php
session_start();
error_reporting(E_ERROR);
$zh=$_POST['zh'];
$password=$_POST['password'];
$user=$_POST['user'];
if(!isset($user)){
echo "<script> alert('请选择用户类型');</script>";
echo "<script> history.go(-1);</script>";
}
$conn=mysqli_connect("localhost","8admin","8admin")or die('连接数据库失败');
$db=mysqli_select_db($conn,"8_com");
$sql1="SELECT*FROM admin WHERE admin_id ='$zh' AND password='$password' ";
$sql2="select * from teacher where teach_id ='$zh' and password='$password' ";
$sql3="select * from student where stuno ='$zh' and password='$password' ";
mysqli_query($conn,"set names utf8");
switch($user){
case 1:$result=mysqli_query($conn,$sql)or die('查询不到');
$row = mysqli_fetch_array($conn,$result);
$count=$row[0];
if($count!=""){
$url="index_admin.php";
$_SESSION['admin_name']=$row['name'];
$_SESSION['admin_id']=$row['admin_id'];
echo "<script type='text/javascript'>"."location.href='".$url."'"."</script>";
}
else {
echo "<script> alert('账户或密码错误');</script>";
echo "<script> history.go(-1);</script>";
}
break;
case 2:$result=mysqli_query($sql2,$conn);
$result=mysqli_query($sql2,$conn)or die('查询不到');
$row = mysqli_fetch_array($result);
$count=$row[0];
if($count!=""){
$url="index_teacher.php";
$_SESSION['teacher_name']=$row['name'];
$_SESSION['teacher_id']=$row['teach_id'];
echo "<script type='text/javascript'>"."location.href='".$url."'"."</script>";
}
else {
echo "<script> alert('账户或密码错误');</script>";
echo "<script> history.go(-1);</script>";
}
break;
case 3:$result=mysqli_query($sql3,$conn);
$result=mysqli_query($sql3,$conn)or die('查询不到');
$row = mysqli_fetch_array($result);
$count=$row[0];
if($count!=""){
$url="index_stu.php";
$_SESSION['stu_name']=$row['name'];
$_SESSION['stu_id']=$row['stuno'];
echo "<script type='text/javascript'>"."location.href='".$url."'"."</script>";
}
else {
echo "<script> alert('账户或密码错误');</script>";
echo "<script> history.go(-1);</script>";
}
break;
default :break;
}
mysqli_close($conn);
?>
问题解答
回答1:后端断点打印是否能够拿到数据