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javascript,$。ajax,变量名

【字号: 日期:2024-04-23 13:47:43浏览:37作者:猪猪
如何解决javascript,$。ajax,变量名?

您可以使用.queue(),$.map()以保持范围name。此外,改变status阵列的具有属性的对象status,其中值是一个数组,以防止可能出现的冲突this.status的Person对象。

请注意,您也可以连接.promise(/* queueName*/)在执行任务.then()时,在所有排队的功能queueName,IEG,'status'一直呼吁,queueName.length是0。

function Person(name, status){ this.name = name; this.status = status;}var blob = new Blob([’{'stream':null}’], {type:'application/json'});var url = URL.createObjectURL(blob);// change `status` array reference, e.g., to `arr`var arr = {status:[]};var array = ['bill','bob','carl','ton'];$(arr).queue('status', $.map(array, function(curr) { return function(next) { var name = curr; // do asynchronous stuff $.ajax({url:url, dataType:'json'}) .then(function(data) { if(data.stream == null){ var person = new Person(name, 'dead'); console.log(name, person); arr.status.push(person); } }) .then(next) // call next function in `'status'` queue }})).dequeue('status').promise('status')// do stuff when all functions in `'status'` queue have completed,// `'status'` queue `.length` is `0`.then(function() { // `this` : `arr` as jQuery object // `this[0].status`: array containing objects pushed to `arr.status` console.log(this[0].status); // $(this).prop('status');});<script src='https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js'></script>

jsfiddle https://jsfiddle.net/nnayjckc/2/

您也可以使用$.when(),.apply(),$.map(),返回相同的结果

function Person(name, status) { this.name = name; this.status = status;}var blob = new Blob([’{'stream':null}’], { type: 'application/json'});var url = URL.createObjectURL(blob);// change `status` array reference, e.g., to `arr`var arr = { status: []};var array = ['bill', 'bob', 'carl', 'ton'];$.when.apply($, $.map(array, function(curr) { var name = curr; return $.ajax({ url: url, dataType: 'json' }) .then(function(data) { if (data.stream == null) {var person = new Person(name, 'dead');console.log(name, person);arr.status.push(person); } })})).then(function() { console.log(arr.status)});<script src='https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js'></script>

jsfiddle https://jsfiddle.net/nnayjckc/3/

解决方法

我正在尝试遍历数组,并为for循环分配变量。所以像这样:

function Person(name,status){ this.name = name; this.status = status;}var status = [];var array = ['bill','bob','carl','ton'];function exAjax(function(){ for(var i = 0; i < array.length; i++){ var name = array[i]; console.log(name); =====> this gives the correct name $.ajax({ url: xxxxxxx,success: function(data){ if(data.stream === null){ var person = new Person(name,'dead'); console.log(name); =====> return undefined until the last person status.push(person); } } }) name = ''; }})

我遇到的问题是名称没有进入成功功能。我以为js会继续向上查找该变量,如果它在当前作用域中不存在?如果尝试console.logname,我将无法为name变量定义!示波器大师我在做什么错?

标签: JavaScript
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