python绘制汉诺塔

本文实例为大家分享了python绘制汉诺塔的具体代码，供大家参考，具体内容如下

源码：

import turtleclass Stack: def __init__(self): self.items = [] def isEmpty(self): return len(self.items) == 0 def push(self, item): self.items.append(item) def pop(self): return self.items.pop() def peek(self): if not self.isEmpty(): return self.items[len(self.items) - 1] def size(self): return len(self.items)def drawpole_3(): # 画出汉诺塔的poles t = turtle.Turtle() t.hideturtle() def drawpole_1(k): t.up() t.pensize(10) t.speed(100) t.goto(400 * (k - 1), 100) t.down() t.goto(400 * (k - 1), -100) t.goto(400 * (k - 1) - 20, -100) t.goto(400 * (k - 1) + 20, -100) drawpole_1(0) # 画出汉诺塔的poles[0] drawpole_1(1) # 画出汉诺塔的poles[1] drawpole_1(2) # 画出汉诺塔的poles[2]def creat_plates(n): # 制造n个盘子 plates = [turtle.Turtle() for i in range(n)] for i in range(n): plates[i].up() plates[i].hideturtle() plates[i].shape('square') plates[i].shapesize(1, 8 - i) plates[i].goto(-400, -90 + 20 * i) plates[i].showturtle() return platesdef pole_stack(): # 制造poles的栈 poles = [Stack() for i in range(3)] return polesdef moveDisk(plates, poles, fp, tp): # 把poles[fp]顶端的盘子plates[mov]从poles[fp]移到poles[tp] mov = poles[fp].peek() plates[mov].goto((fp - 1) * 400, 150) plates[mov].goto((tp - 1) * 400, 150) l = poles[tp].size() # 确定移动到底部的高度（恰好放在原来最上面的盘子上面） plates[mov].goto((tp - 1) * 400, -90 + 20 * l)def moveTower(plates, poles, height, fromPole, toPole, withPole): # 递归放盘子 if height >= 1: moveTower(plates, poles, height - 1, fromPole, withPole, toPole) moveDisk(plates, poles, fromPole, toPole) poles[toPole].push(poles[fromPole].pop()) moveTower(plates, poles, height - 1, withPole, toPole, fromPole)myscreen = turtle.Screen()drawpole_3()n = int(input('请输入汉诺塔的层数并回车:n'))plates = creat_plates(n)poles = pole_stack()for i in range(n): poles[0].push(i)moveTower(plates, poles, n, 0, 2, 1)myscreen.exitonclick()

效果图：

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