python实现逻辑回归的示例

代码

import numpy as npimport matplotlib.pyplot as pltfrom sklearn.datasets.samples_generator import make_classificationdef initialize_params(dims): w = np.zeros((dims, 1)) b = 0 return w, bdef sigmoid(x): z = 1 / (1 + np.exp(-x)) return zdef logistic(X, y, w, b): num_train = X.shape[0] y_hat = sigmoid(np.dot(X, w) + b) loss = -1 / num_train * np.sum(y * np.log(y_hat) + (1-y) * np.log(1-y_hat)) cost = -1 / num_train * np.sum(y * np.log(y_hat) + (1 - y) * np.log(1 - y_hat)) dw = np.dot(X.T, (y_hat - y)) / num_train db = np.sum(y_hat - y) / num_train return y_hat, cost, dw, dbdef linear_train(X, y, learning_rate, epochs): # 参数初始化 w, b = initialize_params(X.shape[1]) loss_list = [] for i in range(epochs): # 计算当前的预测值、损失和梯度 y_hat, loss, dw, db = logistic(X, y, w, b) loss_list.append(loss) # 基于梯度下降的参数更新 w += -learning_rate * dw b += -learning_rate * db # 打印迭代次数和损失 if i % 10000 == 0: print('epoch %d loss %f' % (i, loss)) # 保存参数 params = { ’w’: w, ’b’: b } # 保存梯度 grads = { ’dw’: dw, ’db’: db } return loss_list, loss, params, gradsdef predict(X, params): w = params[’w’] b = params[’b’] y_pred = sigmoid(np.dot(X, w) + b) return y_predif __name__ == '__main__': # 生成数据 X, labels = make_classification(n_samples=100, n_features=2, n_informative=2, n_redundant=0, random_state=1, n_clusters_per_class=2) print(X.shape) print(labels.shape) # 生成伪随机数 rng = np.random.RandomState(2) X += 2 * rng.uniform(size=X.shape) # 划分训练集和测试集 offset = int(X.shape[0] * 0.9) X_train, y_train = X[:offset], labels[:offset] X_test, y_test = X[offset:], labels[offset:] y_train = y_train.reshape((-1, 1)) y_test = y_test.reshape((-1, 1)) print(’X_train=’, X_train.shape) print(’y_train=’, y_train.shape) print(’X_test=’, X_test.shape) print(’y_test=’, y_test.shape) # 训练 loss_list, loss, params, grads = linear_train(X_train, y_train, 0.01, 100000) print(params) # 预测 y_pred = predict(X_test, params) print(y_pred[:10])

以上就是python实现逻辑回归的示例的详细内容，更多关于python 逻辑回归的资料请关注好吧啦网其它相关文章！