Python 解析xml文件的示例

1、获取xml树

import xml.etree.ElementTree as ETdef getTree(xmlName): xmlName = xmlName.strip() try: tree = ET.parse(xmlName) except: tree = None print ’Analysis xml file fail,file name: {}’.format(xmlName) return tree

2、获取根节点

def getRoot(tree): if tree is not None: root = tree.getroot() else: root = None print ’Get root fail’ return root

3、查看根节点

def seeRoot(root): ’’’<country name='tan'>我是小明</country>’’’ if root is not None: print ’root tag:’, root.tag # 标签（country） print ’root attrib:’, root.attrib # ?傩裕?ame='tan'） print ’root text:’, root.text # 文本（我是小明） print ’root tail:’, root.tail # 尾字符串（未涉及）

4、从根开始遍历树

def traverseRoot(root): if root is not None: for label1 in root: print ’label1 tag:’, label1.tag print ’label1 attrib:’, label1.attrib print ’label1 text:’, label1.text print ’label1 tail:’, label1.tail print ’==================’ for label2 in label1:print ’label2 tag:’, label2.tagprint ’label2 attrib:’, label2.attribprint ’label2 text:’, label2.textprint ’label2 tail:’, label2.tailprint ’==================’for label3 in label2: print ’label3 tag:’, label3.tag print ’label3 attrib:’, label3.attrib print ’label3 text:’, label3.text print ’label3 tail:’, label3.tail print ’==================’

5、找到2012年的gdppc和neighbor下的b标签（找到同层有条件的同层另一个tag的文本）

def findYouNedd(root): ’’’查找year为2012下的b标签的文本’’’ if root is not None: for label1 in root: for label2 in label1:if label1.tag == ’country’ and label2.text == ’2012’: # 找到本层标签为country且下一层有2012文本 print ’Find tag为country and next year=2012’ for child in label1: if child.tag == ’gdppc’: print child.text for youNeed in child: if youNeed.tag == ’b’:print ’You need:’, youNeed.text

6、查找父节点下的子节点

def findChildNode(fatherNode, childNode): childNode = childNode.strip() if fatherNode is not None: childs = fatherNode.findall(childNode) print childs print len(childs)

7、另一种办法实现第4点

def findYouNedd2(root): countryNodes = root.findall(’country’) if root is not None: for countryNode in countryNodes: if countryNode.find(’year’).text == ’2012’:print countryNode.find(’gdppc’).text

8、移除节点

def delNode(tree, nodeName): nodeName = nodeName.strip() if tree is not None: root = tree.getroot() findNode = root.find(nodeName) if findNode is not None and findNode.tag == nodeName: root.remove(findNode) tree.write(’removeNode.xml’) # 移除节点后新的xml

9、xml样例（xmlDemo.xml）

<?xml version='1.0'?><data> <country name='Liechtenstein'> <rank>1</rank> <year>2008</year> <gdppc>141100</gdppc> <neighbor name='Austria' direction='E'/> <neighbor name='Switzerland' direction='W'/> </country> <country name='Singapore'> <rank>4</rank> <year>2011</year> <gdppc>59900</gdppc> <neighbor name='Malaysia' direction='N'>123 <a name='a'> aaa </a> </neighbor> </country> <country name='Singapore'> <rank>68</rank> <year>2012</year> <gdppc>13600</gdppc> <neighbor name='Costa Rica' direction='W'/> <neighbor name='Colombia' direction='E'>456 <b name='b'> bbb </b> </neighbor> </country> <city>789</city></data>

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