python实现简单井字棋游戏

井字棋，英文名叫Tic-Tac-Toe，是一种在3*3格子上进行的连珠游戏，和五子棋类似，由于棋盘一般不画边框，格线排成井字故得名。游戏需要的工具仅为纸和笔，然后由分别代表O和X的两个游戏者轮流在格子里留下标记（一般来说先手者为X），任意三个标记形成一条直线，则为获胜。

游戏的难点在于，如何判断连接成了一条线；横、竖、斜三个方向；

游戏的代码：

#!/usr/bin/env python3# -*- coding:utf-8 -*-u’’’Created on 2019年4月13日@author: wuluo’’’__author__ = ’wuluo’__version__ = ’1.0.0’__company__ = u’重庆交大’__updated__ = ’2019-04-13’# 创建井字棋的程序def initBoard(): global board # 调用全局的board board = [None] * 3 print('井字棋：') for i in range(len(board)): board[i] = ['+ '] * 3# 打印井字棋的程序def printBoard(): global board for i in range(len(board)): for j in range(len(board[i])): print(board[i][j], end=' ') print('')# 开始下棋的程序def startGame(): global board player = 0 while isGameContinue(): if player <= 8: if player % 2 == 0: # 甲方下棋 print('==>黑方下棋') if not playChess('x'): continue else: # 乙方下棋 print('==>白方下棋') if not playChess('○'): continue player += 1 else: print('平局') breakdef playChess(chess): # 获取位置 x = int(input('==> X=')) - 1 y = int(input('==> Y=')) - 1 if board[x][y] == '+ ': board[x][y] = chess printBoard() return True # 落子成功 else: print('==> 已有棋子 请重新落子a') printBoard() return False # 落子失败def isGameContinue(): for i in range(len(board)): for j in range(len(board[i])): if board[i][j] != '+ ': # 横向 if j == 0: if board[i][j] == board[i][j + 1] == board[i][j + 2]: whoWin(i, j) return False # 竖向 if i == 0: if board[i][j] == board[i + 1][j] == board[i + 2][j]: whoWin(i, j) return False # 正斜 if i == 0 and j == 0: if board[i][j] == board[i + 1][j + 1] == board[i + 2][j + 2]: whoWin(i, j) return False # 反斜 if i == 2 and j == 0: if board[i][j] == board[i - 1][j + 1] == board[i - 2][j + 2]: whoWin(i, j) return False return Truedef whoWin(i, j): if board[i][j] == 'x': print('黑方胜！') else: print('白方胜！') for i in range(3): print('win')class main(): board = [] initBoard() printBoard() startGame()if __name__ == '__main__': main()

游戏结果：

还有一种结果是平局：

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