Java多线程通信:交替打印ABAB实例

使用wait()和notify()实现Java多线程通信：两个线程交替打印A和B，如ABABAB

public class Test { public static void main(String[] args) { final PrintAB print = new PrintAB(); new Thread(new Runnable() { public void run(){for(int i=0;i<5;i++) { print.printA(); } } }).start(); new Thread(new Runnable() { public void run() {for(int i=0;i<5;i++) { print.printB(); } } }).start(); } } class PrintAB{ private boolean flag = true; public synchronized void printA () { while(!flag) {try { this.wait();} catch (InterruptedException e) { e.printStackTrace(); } }System.out.print('A'); flag = false; this.notify(); } public synchronized void printB () { while(flag) {try { this.wait();} catch (InterruptedException e) { e.printStackTrace();} } System.out.print('B'); flag = true; this.notify(); } }

补充知识：Java多个线程顺序打印数字

要求

启动N个线程, 这N个线程要不间断按顺序打印数字1-N. 将问题简化为3个线程无限循环打印1到3

方法一: 使用synchronized

三个线程无序竞争同步锁, 如果遇上的是自己的数字, 就打印. 这种方式会浪费大量的循环

public class TestSequential1 { private volatile int pos = 1; private volatile int count = 0; public void one(int i) { synchronized (this) { if (pos == i) {System.out.println('T-' + i + ' ' + count);pos = i % 3 + 1;count = 0; } else {count++; } } } public static void main(String[] args) { TestSequential1 demo = new TestSequential1(); for (int i = 1; i <=3; i++) { int j = i; new Thread(()->{while(true) { demo.one(j);} }).start(); } }}

输出

T-1 0T-2 5793T-3 5285T-1 2616T-2 33T-3 28T-1 22T-2 44T-3 6T-1 881T-2 118358T-3 247380T-1 30803T-2 29627T-3 52044...

方法二: 使用synchronized配合wait()和notifyAll()

竞争同步锁时使用wait()和notifyAll(), 可以避免浪费循环

public class TestSequential4 { private volatile int pos = 1; private volatile int count = 0; private final Object obj = new Object(); public void one(int i) { System.out.println(i + ' try'); synchronized (obj) { System.out.println(i + ' in'); try {while (pos != i) { count++; System.out.println(i + ' wait'); obj.wait();}System.out.println('T-' + i + ' ' + count);pos = i % 3 + 1;count = 0;obj.notifyAll(); } catch (InterruptedException e) {e.printStackTrace(); } } } public static void main(String[] args) { TestSequential4 demo = new TestSequential4(); for (int i = 3; i >=1; i--) { int j = i; new Thread(()->{while(true) { demo.one(j);} }).start(); } }}

输出

3 try3 in3 wait2 try2 in2 wait1 try1 inT-1 21 try1 in1 waitT-2 12 try2 in2 waitT-3 13 try3 in3 wait2 waitT-1 21 try1 in1 waitT-2 12 try2 in2 waitT-3 13 try3 in3 wait2 waitT-1 21 try1 in1 waitT-2 12 try2 in2 waitT-3 13 try3 in3 wait2 waitT-1 21 try1 in1 waitT-2 12 try2 in2 waitT-3 13 try3 in3 wait2 waitT-1 21 try1 in1 waitT-2 12 try2 in2 waitT-3 13 try3 in3 wait2 waitT-1 21 try1 in1 waitT-2 12 try2 in2 waitT-3 13 try3 in3 wait2 waitT-1 21 try1 in1 waitT-2 12 try2 in2 waitT-3 13 try3 in3 wait2 waitT-1 21 try1 in1 waitT-2 12 try2 in2 waitT-3 13 try3 in3 wait2 waitT-1 21 try1 in1 waitT-2 12 try2 in2 waitT-3 13 try3 in3 wait2 waitT-1 2...

方法三: 使用可重入锁

用Lock做, 非公平锁, 三个线程竞争, 如果遇上的是自己的数字, 就打印. 这种方式也会浪费大量的循环

public class TestSequential2 { private final Lock lock = new ReentrantLock(); private volatile int pos = 1; private volatile int count = 0; public void one(int i) { lock.lock(); if (pos == i) { System.out.println('T-' + i + ' ' + count); pos = i % 3 + 1; count = 0; } else { count++; } lock.unlock(); } public static void main(String[] args) { TestSequential2 demo = new TestSequential2(); for (int i = 1; i <=3; i++) { int j = i; new Thread(()->{while(true) { demo.one(j);} }).start(); } }}

输出

T-1 0T-2 0T-3 323T-1 54T-2 68964T-3 97642T-1 6504T-2 100603T-3 6989T-1 1313T-2 0T-3 183741T-1 233T-2 5081T-3 164367..

方法四: 使用可重入锁, 启用公平锁

和3一样, 但是使用公平锁, 这种情况下基本上可以做到顺序执行, 偶尔会产生多一次循环

private final Lock lock = new ReentrantLock(true);

输出

T-1 0T-2 0T-3 0T-1 0T-2 0T-3 0T-1 0T-2 0T-3 0T-1 0T-2 0T-3 1T-1 1T-2 1T-3 1...

方法五: 使用Condition

每个线程如果看到不是自己的计数, 就await(), 如果是自己的计数, 就完成打印动作, 再signalAll()所有其他线程去继续运行, 自己在下一个循环后, 即使又继续执行, 也会因为计数已经变了而await.

如果ReentrantLock构造参数使用true, 可以基本消除 ~await 这一步的输出.

public class ReentrantLockCondition2 { private static Lock lock = new ReentrantLock(); private static Condition condition = lock.newCondition(); private volatile int state = 1; private void handle(int state) { lock.lock(); try { while(true) {while(this.state != state) { System.out.println(state + ' ~await'); condition.await();}System.out.println(state);this.state = state % 3 + 1;condition.signalAll();System.out.println(state + ' await');condition.await(); } } catch (InterruptedException e) { e.printStackTrace(); } finally { lock.unlock(); } } public static void main(String[] args) { ReentrantLockCondition2 rlc = new ReentrantLockCondition2(); new Thread(()->rlc.handle(1)).start(); new Thread(()->rlc.handle(2)).start(); new Thread(()->rlc.handle(3)).start(); }}

方法六: 使用多个Condition

给每个线程不同的condition. 这个和4的区别是, 可以用condition.signal()精确地通知对应的线程继续执行(在对应的condition上await的线程, 可能是多个). 这种情况下是可以多个线程都不unlock锁的情况下进行协作的. 注意下面的while(true)循环是在lock.lock()方法内部的.

public class ReentrantLockCondition { private static Lock lock = new ReentrantLock(); private static Condition[] conditions = {lock.newCondition(), lock.newCondition(), lock.newCondition()}; private volatile int state = 1; private void handle(int state) { lock.lock(); try { while(true) {while(this.state != state) { conditions[state - 1].await();}System.out.println(state);this.state = state % 3 + 1;conditions[this.state - 1].signal();conditions[state - 1].await(); } } catch (InterruptedException e) { e.printStackTrace(); } finally { lock.unlock(); } } public static void main(String[] args) { ReentrantLockCondition rlc = new ReentrantLockCondition(); new Thread(()->rlc.handle(1)).start(); new Thread(()->rlc.handle(2)).start(); new Thread(()->rlc.handle(3)).start(); }}

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