PHP接收json并将接收数据插入数据库

最近有一个需求，前端向后台提交json，后台解析并且将提交的值插入数据库中，

<?phprequire (’connect.php’);/*本例用到的数据：post_array={'order_id':'0022015112305010013','buyer_id':'2','seller_id':'1','all_price':'100.00','json_list':[{'product_id':'3','product_number':'3'},{'product_id':'8','product_number':'2'},{'product_id':'10','product_number':'4'}]} */$post_array=$_POST[’post_array’];//--解析Json，获取对应的变量值$obj=json_decode($post_array,TRUE);$order_id = $obj[’order_id’];$buyer_id = $obj[’buyer_id’];$seller_id = $obj[’seller_id’];$all_price = $obj[’all_price’];$i=0;//循环变量//--得到Json_list数组长度$num=count($obj['json_list']);//--遍历数组，将对应信息添加入数据库for ($i;$i<$num;$i++){$list_product_id[]=$obj['json_list'][$i]['product_id'];$list_product_number[]=$obj['json_list'][$i]['product_number'];$insert_order_product_sql='INSERT INTO tbl_order_product (order_id,product_id,product_number) VALUES (?,?,?)';$result = $sqlconn -> prepare($insert_order_product_sql);$result -> bind_param('sss', $order_id,$list_product_id[$i],$list_product_number[$i]);$result->execute();}//--添加订单信息$insert_order_sql='INSERT INTO tbl_order (order_id,buyer_id,seller_id,all_price) VALUES (?,?,?,?)';$result=$sqlconn->prepare($insert_order_sql);$result->bind_param('ssss',$order_id,$buyer_id,$seller_id,$all_price);$result->execute();$result -> close();$sqlconn -> close();?>

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昵称: Hola

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