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Vue实现用户没有登陆时,访问后自动跳转登录页面的实现思路
目录
- 设计思路
- 代码实现
设计思路
- 定义路由的时候配置属性,这里使用needLogin标记访问页面是否需要登录
- 设置路由守卫,每个页面在跳转之前都要经过验证,校验用户信息是否存在,不存在跳转到登录页
- 用户登录后将用户信息存储在localStorage
- 退出登录后,将用户信息清空
代码实现
1、router文件夹的index.js文件中
- 在router中每个地址在meta属性中配置needLogin熟悉,判断访问页面是否需要登录
- 404页面放在最后,匹配所有链接,实现输入不存在的地址时自动跳转404页面
import Vue from "vue"import Router from "vue-router"import LoginCard from "../components/LoginCard";import Home from "../components/Home";import ErrorPage from "../components/ErrorPage";Vue.use(Router)export default new Router({ routes: [ { path: "/", name: "LoginCard", component: LoginCard, meta: {needLogin: false } }, { path: "/loginCard", name: "LoginCard", component: LoginCard, meta: {needLogin: false } }, { path: "/home", name: "Home", component: Home, meta: {needLogin: true } }, { path: "/*", name: "ErrorPage", component: ErrorPage, meta:{needLogin: false } } ]})
2、在main.js中定义一个路由前置守卫,每次跳转页面进行判断,没有登陆自动挑战登陆界面
import Vue from "vue"import App from "./App"import router from "./router"import VueRouter from "vue-router";import ElementUI from "element-ui"import "element-ui/lib/theme-chalk/index.css"import * as auth from "./utils/auth"import store from "./store"import Vuex from "vuex";Vue.config.productionTip = false;Vue.use(ElementUI);Vue.use(VueRouter);Vue.use(Vuex)//这个方法需要放在new Vue之前,不然按F5刷新页面不会调用这个方法router.beforeEach(function (to, from, next) { console.log("是否需要登录才能访问") if (to.meta.needLogin) { if (auth.getAdminInfo()) { console.log(auth.getAdminInfo()) console.log("有cookie信息") next(); }else { console.log("无cookie信息") next({path:"/loginCard" }); } }else{ next(); }})new Vue({ el: "#app", router, store, components: { App }, template: "<App/>"})
3、编写一个存储数据的工具,使用cookie存储用户登录后的信息
import Cookies from "js-cookie"const adminInfo = "adminInfo"//获取用户信息export function getAdminInfo() { const admin = Cookies.get(adminInfo) if(admin){ return JSON.parse(admin) } return ""}//存储用户信息export function setAdminInfo(admin) { return Cookies.set(adminInfo, JSON.stringify(admin))}//移除用户信息export function removeAdminInfo() { return Cookies.remove(adminInfo)}
4、写一个登录页面,用户登录后就将数据存储在cookie中
<template> <div> <el-form ref="loginForm" :rules="formRules" :model="loginUser" label-width="80px"> <h3>欢迎登录</h3> <el-form-item label="用户名" prop="username"><el-input prefix-icon="el-icon-user" type="text" v-model="loginUser.username" placeholder="请输入用户名" :maxlength="50" clearable></el-input> </el-form-item> <el-form-item label="密码" prop="password"><el-input prefix-icon="el-icon-lock" type="password" v-model="loginUser.password" placeholder="请输入密码" :maxlength="50" clearable></el-input> </el-form-item> <el-form-item><el-button type="primary" @click="onSubmit">登陆</el-button><el-button icon="" @click="resetForm">重置</el-button> </el-form-item> </el-form> </div></template><script>import * as auth from "../utils/auth"export default { name: "LoginCard", data() { return { loginUser: {username: "",password: "", }, formRules: {//制定表单输入的规则username: [{required: true, message: "用户名不能为空", trigger: "blur"}],password: [{required: true, message: "密码不能为空", trigger: "blur"}] } } }, methods: { onSubmit() { //判断表单是否符合规则 this.$refs["loginForm"].validate((valid) => { if (valid) { if (this.loginUser.username !== "123456" || this.loginUser.password !== "123456"){ this.$message({message:"账号或密码错误",type: "error", }); return; } auth.setAdminInfo(this.loginUser); this.$router.push({path:"/home"}); }} ) }, resetForm(){ this.$refs["loginForm"].resetFields(); }, }}</script><style scoped>.login-box { border: 1px solid #DCDFE6; width: 400px; margin: 180px auto; padding: 35px 35px 15px 35px; border-radius: 5px;}</style>
5、编写一个退出页面,用户退出以后,将用户信息从cookie中去除,跳转到登陆页面
<template> <div> <h1>主页面</h1> <el-button @click="logout">退出登录</el-button> </div></template><script>import * as auth from "../utils/auth"export default { name : "Home", data() { return { }; }, methods: { logout(){ auth.removeAdminInfo(); this.$router.push({path:"/loginCard"}); } }, mounted() { }}</script>
基本目录结构是这样的
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