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PHP5对Mysql5的任意数据库表的管理代码示例(二)

【字号: 日期:2024-02-14 15:16:35浏览:21作者:猪猪

续:点击添加一个条目就会跳转到add.php //add.php <html><head><title>Add an entry to the database</title><meta http-equiv='Content-Type' content='text/html; charset=gb2312' /></head><body bgcolor=#ffffff><h2>Add an entry</h2><?php$database = 'sunsite';$tablename = $_GET['tablename'];mysql_connect('localhost','root','') or die ('Problem connecting to DataBase');$query = 'show columns from $tablename';$result = mysql_db_query($database,$query);$column = 0;if ($result){while ($r = mysql_fetch_array($result)){$colname[$column] = $r[0];$column = $column + 1;}mysql_free_result($result);}$id = 0;do{$id++;$query = 'select * from $tablename where $colname[0]='$id'';$result = mysql_db_query($database,$query);}while(mysql_fetch_array($result))?><form method='post' action='addsoftware.php'><table width=90% align=center><tr><td><?php echo '$colname[0]';?>:</td><td><?php echo '$id'; ?></td></tr><?for ($col=1;$col<$column;$col++)echo '<tr><td>$colname[$col]:</td><td><input type=text name=$colname[$col] size='100%'></td></tr>';?><input type=hidden name='<?php echo '$colname[0]'; ?>' value='<?php echo '$id'; ?>'><input type=hidden name=tablename value='<?php echo '$tablename'; ?>'><tr><td></td><td><input type=submit value='; Add; '></td></tr></table></form><a href='https://www.haobala.com/bcjs/tables.php?tablename=<? echo '$tablename'?>'>Finish</a></body></html> 其中id是自动寻找并生成的,而且保证在数据库中id是唯一的。点击add之后会将内容写入数据库,然后会继续让你添加内容,直至添加完毕点击finish回到上一层,显示出添加条目後的数据库内容。下面是添加过程中对数据库进行操作的addsoftware.php //addsoftware.php <?php$database = 'sunsite';$tablename = $_POST['tablename'];mysql_connect('localhost','root','') or die ('Problem connecting to DataBase');$query = 'show columns from $tablename';$result = mysql_db_query($database,$query);$column = 0;if ($result){while ($r = mysql_fetch_array($result)){$colname[$column] = $r[0];$column = $column + 1;}mysql_free_result($result);}

for($col=0;$col<$column;$col++)$para[$col] = $_POST[$colname[$col]];

if ($_POST['name']){mysql_connect('localhost','root','') or die ('Problem connecting to DataBase');$query = 'insert into $tablename values ('$para[0]' ';for($col=1;$col<$column;$col++)$query = $query . ','' . $para[$col] . '''; $query = $query . ');';

$result = mysql_db_query($database, $query);Header('Location: add.php?tablename=$tablename');}else{echo 'No name Entered. Please go back and reenter name';} ?><meta http-equiv='Content-Type' content='text/html; charset=gb2312' />待续。

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